f(3/2)=2.3^3/2

Solution for f(3/2)=2.3^3/2 equation:

f(3/2)=2.3^3/2

We move all terms to the left:

f(3/2)-(2.3^3/2)=0

We add all the numbers together, and all the variables

f(+3/2)-(2.3^3/2)=0

We multiply parentheses

3f^2-(2.3^3/2)=0

We get rid of parentheses

3f^2-2.3^3/2=0

We multiply all the terms by the denominator


3f^2*2-2.3^3=0

We add all the numbers together, and all the variables

3f^2*2-12.167=0

Wy multiply elements

6f^2-12.167=0

a = 6; b = 0; c = -12.167;
Δ = b2-4ac
Δ = 02-4·6·(-12.167)
Δ = 292.008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{292.008}}{2*6}=\frac{0-\sqrt{292.008}}{12}
=-\frac{\sqrt{}}{12}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{292.008}}{2*6}=\frac{0+\sqrt{292.008}}{12}
=\frac{\sqrt{}}{12}
$